qemuProcessReadLog: Fix memmove arguments

So I can observe this crasher that with freshly started daemon
(and virtlogd enabled) I am trying to startup a domain that
immediately dies (because it's said to use huge pages but I
haven't allocated a single one in the pool). Hardly reproducible
with -O0 or under valgrind. But I just got lucky:

==20469== Invalid write of size 8
==20469==    at 0x4C2E99B: memcpy@GLIBC_2.2.5 (in /usr/lib64/valgrind/vgpreload_memcheck-amd64-linux.so)
==20469==    by 0x217EDD07: qemuProcessReadLog (qemu_process.c:1670)
==20469==    by 0x217EDE1D: qemuProcessReportLogError (qemu_process.c:1696)
==20469==    by 0x217EE8C1: qemuProcessWaitForMonitor (qemu_process.c:1957)
==20469==    by 0x217F6636: qemuProcessLaunch (qemu_process.c:4955)
==20469==    by 0x217F71A4: qemuProcessStart (qemu_process.c:5152)
==20469==    by 0x21846582: qemuDomainObjStart (qemu_driver.c:7396)
==20469==    by 0x218467DE: qemuDomainCreateWithFlags (qemu_driver.c:7450)
==20469==    by 0x21846845: qemuDomainCreate (qemu_driver.c:7468)
==20469==    by 0x5611CD0: virDomainCreate (libvirt-domain.c:6753)
==20469==    by 0x125D9A: remoteDispatchDomainCreate (remote_dispatch.h:3613)
==20469==    by 0x125CB7: remoteDispatchDomainCreateHelper (remote_dispatch.h:3589)
==20469==  Address 0x27a52ad0 is 0 bytes after a block of size 5,584 alloc'd
==20469==    at 0x4C29F80: malloc (in /usr/lib64/valgrind/vgpreload_memcheck-amd64-linux.so)
==20469==    by 0x9B8D1DB: xdr_string (in /lib64/libc-2.21.so)
==20469==    by 0x563B39C: xdr_virLogManagerProtocolNonNullString (log_protocol.c:24)
==20469==    by 0x563B6B7: xdr_virLogManagerProtocolDomainReadLogFileRet (log_protocol.c:123)
==20469==    by 0x164B34: virNetMessageDecodePayload (virnetmessage.c:407)
==20469==    by 0x5682360: virNetClientProgramCall (virnetclientprogram.c:379)
==20469==    by 0x563B30E: virLogManagerDomainReadLogFile (log_manager.c:272)
==20469==    by 0x217CD613: qemuDomainLogContextRead (qemu_domain.c:2485)
==20469==    by 0x217EDC76: qemuProcessReadLog (qemu_process.c:1660)
==20469==    by 0x217EDE1D: qemuProcessReportLogError (qemu_process.c:1696)
==20469==    by 0x217EE8C1: qemuProcessWaitForMonitor (qemu_process.c:1957)
==20469==    by 0x217F6636: qemuProcessLaunch (qemu_process.c:4955)

This points to memmove() in qemuProcessReadLog(). Imagine we just
read the following string from qemu:

"abc\n2016-01-18T09:40:44.022744Z qemu-system-x86_64: Error\n"

After the first pass of the while() loop in the
qemuProcessReadLog() (in which we have taken the false branch in
the if) @buf still points to the beginning of the string,
@filter_next points to the beginning of the second line.  So we
start second iteration because there is yet another newline
character at the end. In this iteration @eol points to it
actually. Now, the control gets inside true branch of if(). Just
to remind you:

got = 58
filter_next = buf + 5,
eol = buf + 58.

Therefore skip = 54 which is correct. The message we want to skip
is 54 bytes long. However:

memmove(filter_next, eol + 1, (got - skip) +1);

which is

memmove(filter_next, eol + 1, 5)

is obviously wrong as there is only one byte we can access, not 5!

Signed-off-by: Michal Privoznik <mprivozn@redhat.com>

src/qemu/qemu_process.c

@@ -1667,7 +1667,7 @@ qemuProcessReadLog(qemuDomainLogContextPtr logCtxt, char **msg)
         if (virLogProbablyLogMessage(filter_next) ||
             STRPREFIX(filter_next, "char device redirected to")) {
             size_t skip = (eol + 1) - filter_next;
-            memmove(filter_next, eol + 1, (got - skip) + 1);
+            memmove(filter_next, eol + 1, buf + got - eol);
             got -= skip;
         } else {
             filter_next = eol + 1;