mirror of https://gitee.com/openkylin/linux.git
lockdep: Print a nicer description for irq lock inversions
Locking order inversion due to interrupts is a subtle problem. When an irq lockiinversion discovered by lockdep it currently reports something like: [ INFO: HARDIRQ-safe -> HARDIRQ-unsafe lock order detected ] ... and then prints out the locks that are involved, as back traces. Judging by lkml feedback developers were routinely confused by what a HARDIRQ->safe to unsafe issue is all about, and sometimes even blew it off as a bug in lockdep. It is not obvious when lockdep prints this message about a lock that is never taken in interrupt context. After explaining the problems that lockdep is reporting, I decided to add a description of the problem in visual form. Now the following is shown: --- other info that might help us debug this: Possible interrupt unsafe locking scenario: CPU0 CPU1 ---- ---- lock(lockA); local_irq_disable(); lock(&rq->lock); lock(lockA); <Interrupt> lock(&rq->lock); *** DEADLOCK *** --- The above is the case when the unsafe lock is taken while holding a lock taken in irq context. But when a lock is taken that also grabs a unsafe lock, the call chain is shown: --- other info that might help us debug this: Chain exists of: &rq->lock --> lockA --> lockC Possible interrupt unsafe locking scenario: CPU0 CPU1 ---- ---- lock(lockC); local_irq_disable(); lock(&rq->lock); lock(lockA); <Interrupt> lock(&rq->lock); *** DEADLOCK *** Signed-off-by: Steven Rostedt <rostedt@goodmis.org> Acked-by: Peter Zijlstra <a.p.zijlstra@chello.nl> Cc: Frederic Weisbecker <fweisbec@gmail.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Andrew Morton <akpm@linux-foundation.org> Link: http://lkml.kernel.org/r/20110421014259.132728798@goodmis.org Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -490,6 +490,18 @@ void get_usage_chars(struct lock_class *class, char usage[LOCK_USAGE_CHARS])
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usage[i] = '\0';
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}
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static int __print_lock_name(struct lock_class *class)
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{
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char str[KSYM_NAME_LEN];
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const char *name;
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name = class->name;
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if (!name)
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name = __get_key_name(class->key, str);
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return printk("%s", name);
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}
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static void print_lock_name(struct lock_class *class)
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{
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char str[KSYM_NAME_LEN], usage[LOCK_USAGE_CHARS];
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@ -1325,6 +1337,62 @@ print_shortest_lock_dependencies(struct lock_list *leaf,
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return;
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}
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static void
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print_irq_lock_scenario(struct lock_list *safe_entry,
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struct lock_list *unsafe_entry,
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struct held_lock *prev,
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struct held_lock *next)
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{
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struct lock_class *safe_class = safe_entry->class;
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struct lock_class *unsafe_class = unsafe_entry->class;
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struct lock_class *middle_class = hlock_class(prev);
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if (middle_class == safe_class)
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middle_class = hlock_class(next);
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/*
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* A direct locking problem where unsafe_class lock is taken
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* directly by safe_class lock, then all we need to show
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* is the deadlock scenario, as it is obvious that the
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* unsafe lock is taken under the safe lock.
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*
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* But if there is a chain instead, where the safe lock takes
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* an intermediate lock (middle_class) where this lock is
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* not the same as the safe lock, then the lock chain is
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* used to describe the problem. Otherwise we would need
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* to show a different CPU case for each link in the chain
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* from the safe_class lock to the unsafe_class lock.
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*/
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if (middle_class != unsafe_class) {
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printk("Chain exists of:\n ");
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__print_lock_name(safe_class);
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printk(" --> ");
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__print_lock_name(middle_class);
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printk(" --> ");
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__print_lock_name(unsafe_class);
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printk("\n\n");
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}
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printk(" Possible interrupt unsafe locking scenario:\n\n");
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printk(" CPU0 CPU1\n");
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printk(" ---- ----\n");
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printk(" lock(");
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__print_lock_name(unsafe_class);
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printk(");\n");
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printk(" local_irq_disable();\n");
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printk(" lock(");
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__print_lock_name(safe_class);
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printk(");\n");
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printk(" lock(");
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__print_lock_name(middle_class);
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printk(");\n");
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printk(" <Interrupt>\n");
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printk(" lock(");
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__print_lock_name(safe_class);
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printk(");\n");
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printk("\n *** DEADLOCK ***\n\n");
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}
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static int
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print_bad_irq_dependency(struct task_struct *curr,
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struct lock_list *prev_root,
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@ -1376,6 +1444,8 @@ print_bad_irq_dependency(struct task_struct *curr,
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print_stack_trace(forwards_entry->class->usage_traces + bit2, 1);
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printk("\nother info that might help us debug this:\n\n");
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print_irq_lock_scenario(backwards_entry, forwards_entry, prev, next);
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lockdep_print_held_locks(curr);
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printk("\nthe dependencies between %s-irq-safe lock", irqclass);
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