iommu/arm-smmu-v3: Fix resource_size check

This is an off-by-one mistake.

resource_size() returns res->end - res->start + 1.

Reviewed-by: Robin Murphy <robin.murphy@arm.com>
Signed-off-by: Masahiro Yamada <yamada.masahiro@socionext.com>
Signed-off-by: Will Deacon <will@kernel.org>
This commit is contained in:
Masahiro Yamada 2019-12-26 18:50:56 +09:00 committed by Will Deacon
parent 935d43ba27
commit 322a9bbb72
1 changed files with 1 additions and 1 deletions

View File

@ -3632,7 +3632,7 @@ static int arm_smmu_device_probe(struct platform_device *pdev)
/* Base address */
res = platform_get_resource(pdev, IORESOURCE_MEM, 0);
if (resource_size(res) + 1 < arm_smmu_resource_size(smmu)) {
if (resource_size(res) < arm_smmu_resource_size(smmu)) {
dev_err(dev, "MMIO region too small (%pr)\n", res);
return -EINVAL;
}