Input: gpio_keys - don't report events on gpio failure

In the cases where the gpio chip fails to acquire the current state an
error is reported back to gpio_keys. This is currently interpreted as if
the line went high, which just confuses the developer.

This patch introduces an error print in this case and skipps the
reporting of a input event; to aid in debugging this issue.

Reported-by: John Stultz <john.stultz@linaro.org>
Signed-off-by: Bjorn Andersson <bjorn.andersson@sonymobile.com>
Reviewed-by: Linus Walleij <linus.walleij@linaro.org>
Signed-off-by: Dmitry Torokhov <dmitry.torokhov@gmail.com>
This commit is contained in:
Bjorn Andersson 2015-10-02 10:44:00 -07:00 committed by Dmitry Torokhov
parent a27b5e0a78
commit 77fa05541c
1 changed files with 7 additions and 1 deletions

View File

@ -341,8 +341,14 @@ static void gpio_keys_gpio_report_event(struct gpio_button_data *bdata)
const struct gpio_keys_button *button = bdata->button;
struct input_dev *input = bdata->input;
unsigned int type = button->type ?: EV_KEY;
int state = (gpio_get_value_cansleep(button->gpio) ? 1 : 0) ^ button->active_low;
int state = gpio_get_value_cansleep(button->gpio);
if (state < 0) {
dev_err(input->dev.parent, "failed to get gpio state\n");
return;
}
state = (state ? 1 : 0) ^ button->active_low;
if (type == EV_ABS) {
if (state)
input_event(input, type, button->code, button->value);