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ext4: convert swap_inode_data() over to use swap() on most of the fields 

For some odd reason, it forces a byte-by-byte copy of each field. A
plain old swap() on most of these fields would be more efficient. We
do need to retain the memswap of i_data however as that field is an array.

Signed-off-by: Theodore Ts'o <tytso@mit.edu>
Signed-off-by: Jeff Layton <jlayton@redhat.com>
Reviewed-by: Jan Kara <jack@suse.cz>
This commit is contained in:
Jeff Layton 2017-07-31 00:55:34 -04:00 committed by Theodore Ts'o
parent 191eac3300
commit 9c5d58fb9e
1 changed files with 8 additions and 10 deletions
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18
fs/ext4/ioctl.c
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@ -64,18 +64,16 @@ static void swap_inode_data(struct inode *inode1, struct inode *inode2)
ei1 = EXT4_I(inode1);
ei2 = EXT4_I(inode2);
memswap(&inode1->i_flags, &inode2->i_flags, sizeof(inode1->i_flags));
memswap(&inode1->i_version, &inode2->i_version,
sizeof(inode1->i_version));
memswap(&inode1->i_blocks, &inode2->i_blocks,
sizeof(inode1->i_blocks));
memswap(&inode1->i_bytes, &inode2->i_bytes, sizeof(inode1->i_bytes));
memswap(&inode1->i_atime, &inode2->i_atime, sizeof(inode1->i_atime));
memswap(&inode1->i_mtime, &inode2->i_mtime, sizeof(inode1->i_mtime));
swap(inode1->i_flags, inode2->i_flags);
swap(inode1->i_version, inode2->i_version);
swap(inode1->i_blocks, inode2->i_blocks);
swap(inode1->i_bytes, inode2->i_bytes);
swap(inode1->i_atime, inode2->i_atime);
swap(inode1->i_mtime, inode2->i_mtime);
memswap(ei1->i_data, ei2->i_data, sizeof(ei1->i_data));
memswap(&ei1->i_flags, &ei2->i_flags, sizeof(ei1->i_flags));
memswap(&ei1->i_disksize, &ei2->i_disksize, sizeof(ei1->i_disksize));
swap(ei1->i_flags, ei2->i_flags);
swap(ei1->i_disksize, ei2->i_disksize);
ext4_es_remove_extent(inode1, 0, EXT_MAX_BLOCKS);
ext4_es_remove_extent(inode2, 0, EXT_MAX_BLOCKS);