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slow_work_thread() should do the exclusive wait 

slow_work_thread() sleeps on slow_work_thread_wq without WQ_FLAG_EXCLUSIVE,
this means that slow_work_enqueue()->__wake_up(nr_exclusive => 1) wakes up all
kslowd threads.  This is not what we want, so we change slow_work_thread() to
use prepare_to_wait_exclusive() instead.

Signed-off-by: Oleg Nesterov <oleg@redhat.com>
Signed-off-by: David Howells <dhowells@redhat.com>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Oleg Nesterov 2009-06-11 13:12:55 +01:00 committed by Linus Torvalds
parent 6adc74b7d0
commit b415c49a86
1 changed files with 2 additions and 2 deletions
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4
kernel/slow-work.c
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@ -372,8 +372,8 @@ static int slow_work_thread(void *_data)
vsmax *= atomic_read(&slow_work_thread_count);
vsmax /= 100;
prepare_to_wait(&slow_work_thread_wq, &wait,
TASK_INTERRUPTIBLE);
prepare_to_wait_exclusive(&slow_work_thread_wq, &wait,
TASK_INTERRUPTIBLE);
if (!freezing(current) &&
!slow_work_threads_should_exit &&
!slow_work_available(vsmax) &&