mirror of https://gitee.com/openkylin/linux.git
[PATCH] s390: memory detection > 32GB
The kernel takes a very long time to boot if the memory size is bigger then 32767 MB. The memory size is contained in a structure created by an sclp call. The kernel accesses the field with a LH instrution which performs a sign extension of a 16 bit word. In the case of a memory size with bit 2^15 set this results in a very large value and the memory detection just loops for a long time. In addition if more then 64 GB are used on a 64 bit system the memory size is read from an incorrect storage location. Use zero-extention to read the 16 bit memory size and the correct offset to read the 4 byte memory size on 64 bit. Signed-off-by: Martin Schwidefsky <schwidefsky@de.ibm.com> Signed-off-by: Andrew Morton <akpm@osdl.org> Signed-off-by: Linus Torvalds <torvalds@osdl.org>
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@ -517,10 +517,10 @@ startup:basr %r13,0 # get base
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l %r2, .Lrcp2-.LPG1(%r13) # try with Read SCP
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b .Lservicecall-.LPG1(%r13)
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.Lprocsccb:
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lh %r1,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
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chi %r1,0x00
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jne .Lscnd
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l %r1,.Lscpincr2-PARMAREA(%r4) # otherwise use this one
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lhi %r1,0
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icm %r1,3,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
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jnz .Lscnd
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l %r1,.Lscpincr2-PARMAREA+4(%r4) # otherwise use this one
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.Lscnd:
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xr %r3,%r3 # same logic
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ic %r3,.Lscpa1-PARMAREA(%r4)
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@ -518,9 +518,9 @@ startup:basr %r13,0 # get base
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l %r2,.Lrcp2-.LPG1(%r13) # try with Read SCP
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b .Lservicecall-.LPG1(%r13)
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.Lprocsccb:
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lh %r1,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
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chi %r1,0x00
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jne .Lscnd
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lghi %r1,0
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icm %r1,3,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
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jnz .Lscnd
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lg %r1,.Lscpincr2-PARMAREA(%r4) # otherwise use this one
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.Lscnd:
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xr %r3,%r3 # same logic
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