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Staging: quickstart: free after input_unregister_device()
input_unregister_device() releases "quickstart_input" so the input_free_device() is a double free. Also I noticed that there is a memory leak if the call to input_register_device() fails. Signed-off-by: Dan Carpenter <error27@gmail.com> Signed-off-by: Greg Kroah-Hartman <gregkh@suse.de>
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@ -355,7 +355,6 @@ static int quickstart_acpi_remove(struct acpi_device *device, int type)
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static void quickstart_exit(void)
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{
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input_unregister_device(quickstart_input);
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input_free_device(quickstart_input);
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device_remove_file(&pf_device->dev, &dev_attr_pressed_button);
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device_remove_file(&pf_device->dev, &dev_attr_buttons);
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@ -375,6 +374,7 @@ static int __init quickstart_init_input(void)
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{
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struct quickstart_btn **ptr = &quickstart_data.btn_lst;
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int count;
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int ret;
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quickstart_input = input_allocate_device();
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@ -391,7 +391,13 @@ static int __init quickstart_init_input(void)
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ptr = &((*ptr)->next);
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}
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return input_register_device(quickstart_input);
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ret = input_register_device(quickstart_input);
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if (ret) {
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input_free_device(quickstart_input);
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return ret;
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}
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return 0;
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}
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static int __init quickstart_init(void)
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