linux/arch/parisc/include/asm/hash.h

147 lines
5.0 KiB
C

#ifndef _ASM_HASH_H
#define _ASM_HASH_H
/*
* HP-PA only implements integer multiply in the FPU. However, for
* integer multiplies by constant, it has a number of shift-and-add
* (but no shift-and-subtract, sigh!) instructions that a compiler
* can synthesize a code sequence with.
*
* Unfortunately, GCC isn't very efficient at using them. For example
* it uses three instructions for "x *= 21" when only two are needed.
* But we can find a sequence manually.
*/
#define HAVE_ARCH__HASH_32 1
/*
* This is a multiply by GOLDEN_RATIO_32 = 0x61C88647 optimized for the
* PA7100 pairing rules. This is an in-order 2-way superscalar processor.
* Only one instruction in a pair may be a shift (by more than 3 bits),
* but other than that, simple ALU ops (including shift-and-add by up
* to 3 bits) may be paired arbitrarily.
*
* PA8xxx processors also dual-issue ALU instructions, although with
* fewer constraints, so this schedule is good for them, too.
*
* This 6-step sequence was found by Yevgen Voronenko's implementation
* of the Hcub algorithm at http://spiral.ece.cmu.edu/mcm/gen.html.
*/
static inline u32 __attribute_const__ __hash_32(u32 x)
{
u32 a, b, c;
/*
* Phase 1: Compute a = (x << 19) + x,
* b = (x << 9) + a, c = (x << 23) + b.
*/
a = x << 19; /* Two shifts can't be paired */
b = x << 9; a += x;
c = x << 23; b += a;
c += b;
/* Phase 2: Return (b<<11) + (c<<6) + (a<<3) - c */
b <<= 11;
a += c << 3; b -= c;
return (a << 3) + b;
}
#if BITS_PER_LONG == 64
#define HAVE_ARCH_HASH_64 1
/*
* Finding a good shift-and-add chain for GOLDEN_RATIO_64 is tricky,
* because available software for the purpose chokes on constants this
* large. (It's mostly designed for compiling FIR filter coefficients
* into FPGAs.)
*
* However, Jason Thong pointed out a work-around. The Hcub software
* (http://spiral.ece.cmu.edu/mcm/gen.html) is designed for *multiple*
* constant multiplication, and is good at finding shift-and-add chains
* which share common terms.
*
* Looking at 0x0x61C8864680B583EB in binary:
* 0110000111001000100001100100011010000000101101011000001111101011
* \______________/ \__________/ \_______/ \________/
* \____________________________/ \____________________/
* you can see the non-zero bits are divided into several well-separated
* blocks. Hcub can find algorithms for those terms separately, which
* can then be shifted and added together.
*
* Dividing the input into 2, 3 or 4 blocks, Hcub can find solutions
* with 10, 9 or 8 adds, respectively, making a total of 11 for the
* whole number.
*
* Using just two large blocks, 0xC3910C8D << 31 in the high bits,
* and 0xB583EB in the low bits, produces as good an algorithm as any,
* and with one more small shift than alternatives.
*
* The high bits are a larger number and more work to compute, as well
* as needing one extra cycle to shift left 31 bits before the final
* addition, so they are the critical path for scheduling. The low bits
* can fit into the scheduling slots left over.
*/
/*
* This _ASSIGN(dst, src) macro performs "dst = src", but prevents GCC
* from inferring anything about the value assigned to "dest".
*
* This prevents it from mis-optimizing certain sequences.
* In particular, gcc is annoyingly eager to combine consecutive shifts.
* Given "x <<= 19; y += x; z += x << 1;", GCC will turn this into
* "y += x << 19; z += x << 20;" even though the latter sequence needs
* an additional instruction and temporary register.
*
* Because no actual assembly code is generated, this construct is
* usefully portable across all GCC platforms, and so can be test-compiled
* on non-PA systems.
*
* In two places, additional unused input dependencies are added. This
* forces GCC's scheduling so it does not rearrange instructions too much.
* Because the PA-8xxx is out of order, I'm not sure how much this matters,
* but why make it more difficult for the processor than necessary?
*/
#define _ASSIGN(dst, src, ...) asm("" : "=r" (dst) : "0" (src), ##__VA_ARGS__)
/*
* Multiply by GOLDEN_RATIO_64 = 0x0x61C8864680B583EB using a heavily
* optimized shift-and-add sequence.
*
* Without the final shift, the multiply proper is 19 instructions,
* 10 cycles and uses only 4 temporaries. Whew!
*
* You are not expected to understand this.
*/
static __always_inline u32 __attribute_const__
hash_64(u64 a, unsigned int bits)
{
u64 b, c, d;
/*
* Encourage GCC to move a dynamic shift to %sar early,
* thereby freeing up an additional temporary register.
*/
if (!__builtin_constant_p(bits))
asm("" : "=q" (bits) : "0" (64 - bits));
else
bits = 64 - bits;
_ASSIGN(b, a*5); c = a << 13;
b = (b << 2) + a; _ASSIGN(d, a << 17);
a = b + (a << 1); c += d;
d = a << 10; _ASSIGN(a, a << 19);
d = a - d; _ASSIGN(a, a << 4, "X" (d));
c += b; a += b;
d -= c; c += a << 1;
a += c << 3; _ASSIGN(b, b << (7+31), "X" (c), "X" (d));
a <<= 31; b += d;
a += b;
return a >> bits;
}
#undef _ASSIGN /* We're a widely-used header file, so don't litter! */
#endif /* BITS_PER_LONG == 64 */
#endif /* _ASM_HASH_H */