input: Write a function that takes a dictionary as an argument and returns an inverted dictionary. In the inverted dictionary, the keys and values of the original dictionary are swapped. If a value appears more than once in the original dictionary, the inverted dictionary should contain a list of keys corresponding to that value.
  
  def invert_dictionary(d):
      inverted_d = {}
      for key, value in d.items():
          if value not in inverted_d:
              inverted_d[value] = []
          inverted_d[value].append(key)
      return inverted_d
  
  assert invert_dictionary({'a': 1, 'b': 2, 'c': 1})=={1: ['a', 'c'], 2: ['b']}
  assert invert_dictionary({'x': 'apple', 'y': 'banana', 'z': 'apple'})=={'apple': ['x', 'z'], 'banana': ['y']}
  assert invert_dictionary({})=={}
  assert invert_dictionary({'one': 1})=={1: ['one']}
output: def invert_dictionary(d):
      inverted_d = {}
      for key, value in d.items():
          if value not in inverted_d:
              inverted_d[value] = []
          inverted_d[value].append(key)
      return inverted_d