input: Write a function to compare two binary trees and determine if they are similar, meaning they have the same structure and values at corresponding nodes. If both trees are empty, they are considered similar. If one tree is empty and the other is not, they are not similar. If the values at corresponding nodes are different, the trees are not similar. Otherwise, recursively check the left and right subtrees.
  
  class TreeNode:
      def __init__(self, x):
          self.val = x
          self.left = None
          self.right = None
  
  def are_similar(root1, root2):
      if root1 is None and root2 is None:
          return True
      if root1 is None or root2 is None:
          return False
      if root1.val != root2.val:
          return False
      return are_similar(root1.left, root2.left) and are_similar(root1.right, root2.right)
  
  assert are_similar(None, None)==True
  assert are_similar(TreeNode(1), None)==False
  assert are_similar(None, TreeNode(1))==False
  assert are_similar(TreeNode(1), TreeNode(1))==True
  assert are_similar(TreeNode(1, TreeNode(2), TreeNode(3)), TreeNode(1, TreeNode(2), TreeNode(3)))==True
  assert are_similar(TreeNode(1, TreeNode(2), TreeNode(3)), TreeNode(1, None, TreeNode(3)))==False
output: def are_similar(root1, root2):
      if root1 is None and root2 is None:
          return True
      if root1 is None or root2 is None:
          return False
      if root1.val != root2.val:
          return False
      return are_similar(root1.left, root2.left) and are_similar(root1.right, root2.right)