input: Write a function to get the third largest element in a given list. If the list has fewer than three elements, it should return None.
  def third_largest(lst):
      if len(lst) < 3:
          return None
      distinct = []
      for i in lst:
          if i not in distinct:
              distinct.append(i)
      distinct.sort(reverse=True)
      return distinct[2] if len(distinct) >= 3 else None
  
  assert third_largest([12, 13, 13, 45, 22, 99])==22
  assert third_largest([10, 20, 40, 30, 50])==30
  assert third_largest([5, 5, 5, 5])==None
  assert third_largest([7, 3, 8, 4, 9, 6, 2])==6
  assert third_largest([1])==None
output: def third_largest(lst):
      if len(lst) < 3:
          return None
      distinct = []
      for i in lst:
          if i not in distinct:
              distinct.append(i)
      distinct.sort(reverse=True)
      return distinct[2] if len(distinct) >= 3 else None