input: Write a function to find the most efficient path for a robot to take from its current location to the destination using a Breadth-First Search algorithm. If the goal is reached, return the path as a list of tuples representing the coordinates visited from the start to the destination. If it is not possible to reach the destination after a certain number of tries, return None. 
  
  def find_path(start, end):
      x = start[0]
      y = start[1]
      goal_x = end[0]
      goal_y = end[1]
      visited = set()
      queue = [([x, y], [])]
      neighbor = [[1, 0], [0, 1], [-1, 0], [0, -1]]
      max_tries = 100
      while queue:
          position, path = queue.pop(0)
          if position[0] == goal_x and position[1] == goal_y:
              return path + [position]
          if position not in visited and max_tries > 0:
              visited.add(position)
              max_tries = max_tries - 1
              for neighbor_x, neighbor_y in neighbor:
                  next_x = position[0] + neighbor_x
                  next_y = position[1] + neighbor_y
                  queue.append(([next_x, next_y], path + [position]))
      return None
  
  assert find_path((4, 2), (9, 9))==[([4, 2], []), [5, 2], [6, 2], [7, 2], [8, 2], [9, 2], [9, 3], [9, 4], [9, 5], [9, 6], [9, 7], [9, 8], [9, 9]]
  assert find_path((1, 1), (3, 3))==[([1, 1], []), [2, 1], [3, 1], [3, 2], [3, 3]]
  assert find_path((0, 0), (5, 5))==None
  assert find_path((0, 0), (1, 1))==[([0, 0], []), [1, 0], [1, 1]]
  assert find_path((10, 10), (10, 10))==[([10, 10], [])]
output: def find_path(start, end):
      x = start[0]
      y = start[1]
      goal_x = end[0]
      goal_y = end[1]
      visited = set()
      queue = [([x, y], [])]
      neighbor = [[1, 0], [0, 1], [-1, 0], [0, -1]]
      max_tries = 100
      while queue:
          position, path = queue.pop(0)
          if position[0] == goal_x and position[1] == goal_y:
              return path + [position]
          if tuple(position) not in visited and max_tries > 0:
              visited.add(tuple(position))
              max_tries = max_tries - 1
              for neighbor_x, neighbor_y in neighbor:
                  next_x = position[0] + neighbor_x
                  next_y = position[1] + neighbor_y
                  queue.append(([next_x, next_y], path + [position]))
      return None