input: def divide_text(txt):
      '''
      Given a string of words, return a list of words divided by spaces; if there are no spaces, split by commas ','; 
      if there are no commas, return the number of lower-case letters with odd positions in the alphabet 
      (where ord('a') = 0, ord('b') = 1, ... ord('z') = 25).
      Examples
      divide_text("Hello world!") ➞ ["Hello", "world!"]
      divide_text("Hello,world!") ➞ ["Hello", "world!"]
      divide_text("abcdef") == 3 
      '''
output:     if ' ' in txt:
          return txt.split(' ')
      elif ',' in txt:
          return txt.split(',')
      else:
          return sum(1 for c in txt if 'a' <= c <= 'z' and (ord(c) - ord('a')) % 2 == 1)