input: Write a Python function that, given an array 'numbers' which is a permutation of [0, 1, 2, ..., n - 1], determines the permutation named 'order' with the smallest possible score. The score of any permutation order of [0, 1, 2, ..., n - 1] is defined as:
  
  score(order) = |order[0] - numbers[order[1]]| + |order[1] - numbers[order[2]]| + ... + |order[n - 1] - numbers[order[0]]|
  
  Return the permutation order that has the minimum score. If there are multiple permutations with the same score, return the lexicographically smallest one.
  
  Examples:
  >>> numbers = [1,0,2]
  [0,1,2]
  >>> numbers = [0,2,1]
  [0,2,1]
  
  Constraints:
  2 <= n == numbers.length <= 14
  numbers is a permutation of [0, 1, 2, ..., n - 1].
output: def find_minimum_score_permutation(numbers):
      from itertools import permutations
  
      def compute_score(perm, numbers):
          n = len(perm)
          score = sum(abs(perm[i] - numbers[perm[(i + 1) % n]]) for i in range(n))
          return score
  
      n = len(numbers)
      min_score = float('inf')
      best_perm = None
  
      for perm in permutations(range(n)):
          score = compute_score(perm, numbers)
          if score < min_score:
              min_score = score
              best_perm = perm
          elif score == min_score and perm < best_perm:
              best_perm = perm
              
      return list(best_perm)