input: def divide_text(txt):
      '''
      Given a string, return a list of words separated by spaces. If there are no whitespaces, split the string using commas ','.
      If neither spaces nor commas are present, return the number of lowercase letters with odd positions in the English alphabet,
      e.g., ord('a') = 0, ord('b') = 1, ... ord('z') = 25
      Examples
      divide_text("Hello world!") ➞ ["Hello", "world!"]
      divide_text("Hello,world!") ➞ ["Hello", "world!"]
      divide_text("abcdef") ➞ 3
      '''
output:     if ' ' in txt:
          return txt.split(' ')
      elif ',' in txt:
          return txt.split(',')
      else:
          odd_positions = [chr(pos + ord('a')) for pos in range(0, 26, 2)]
          count = sum(1 for char in txt if char in odd_positions)
          return count