aosp12/external/antlr/runtime/Python/antlr3/dottreegen.py

211 lines
6.8 KiB
Python

""" @package antlr3.dottreegenerator
@brief ANTLR3 runtime package, tree module
This module contains all support classes for AST construction and tree parsers.
"""
# begin[licence]
#
# [The "BSD licence"]
# Copyright (c) 2005-2008 Terence Parr
# All rights reserved.
#
# Redistribution and use in source and binary forms, with or without
# modification, are permitted provided that the following conditions
# are met:
# 1. Redistributions of source code must retain the above copyright
# notice, this list of conditions and the following disclaimer.
# 2. Redistributions in binary form must reproduce the above copyright
# notice, this list of conditions and the following disclaimer in the
# documentation and/or other materials provided with the distribution.
# 3. The name of the author may not be used to endorse or promote products
# derived from this software without specific prior written permission.
#
# THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
# IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
# OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
# IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
# INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
# NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
# DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
# THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
# (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
# THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
#
# end[licence]
# lot's of docstrings are missing, don't complain for now...
# pylint: disable-msg=C0111
from antlr3.tree import CommonTreeAdaptor
import stringtemplate3
class DOTTreeGenerator(object):
"""
A utility class to generate DOT diagrams (graphviz) from
arbitrary trees. You can pass in your own templates and
can pass in any kind of tree or use Tree interface method.
"""
_treeST = stringtemplate3.StringTemplate(
template=(
"digraph {\n" +
" ordering=out;\n" +
" ranksep=.4;\n" +
" node [shape=plaintext, fixedsize=true, fontsize=11, fontname=\"Courier\",\n" +
" width=.25, height=.25];\n" +
" edge [arrowsize=.5]\n" +
" $nodes$\n" +
" $edges$\n" +
"}\n")
)
_nodeST = stringtemplate3.StringTemplate(
template="$name$ [label=\"$text$\"];\n"
)
_edgeST = stringtemplate3.StringTemplate(
template="$parent$ -> $child$ // \"$parentText$\" -> \"$childText$\"\n"
)
def __init__(self):
## Track node to number mapping so we can get proper node name back
self.nodeToNumberMap = {}
## Track node number so we can get unique node names
self.nodeNumber = 0
def toDOT(self, tree, adaptor=None, treeST=_treeST, edgeST=_edgeST):
if adaptor is None:
adaptor = CommonTreeAdaptor()
treeST = treeST.getInstanceOf()
self.nodeNumber = 0
self.toDOTDefineNodes(tree, adaptor, treeST)
self.nodeNumber = 0
self.toDOTDefineEdges(tree, adaptor, treeST, edgeST)
return treeST
def toDOTDefineNodes(self, tree, adaptor, treeST, knownNodes=None):
if knownNodes is None:
knownNodes = set()
if tree is None:
return
n = adaptor.getChildCount(tree)
if n == 0:
# must have already dumped as child from previous
# invocation; do nothing
return
# define parent node
number = self.getNodeNumber(tree)
if number not in knownNodes:
parentNodeST = self.getNodeST(adaptor, tree)
treeST.setAttribute("nodes", parentNodeST)
knownNodes.add(number)
# for each child, do a "<unique-name> [label=text]" node def
for i in range(n):
child = adaptor.getChild(tree, i)
number = self.getNodeNumber(child)
if number not in knownNodes:
nodeST = self.getNodeST(adaptor, child)
treeST.setAttribute("nodes", nodeST)
knownNodes.add(number)
self.toDOTDefineNodes(child, adaptor, treeST, knownNodes)
def toDOTDefineEdges(self, tree, adaptor, treeST, edgeST):
if tree is None:
return
n = adaptor.getChildCount(tree)
if n == 0:
# must have already dumped as child from previous
# invocation; do nothing
return
parentName = "n%d" % self.getNodeNumber(tree)
# for each child, do a parent -> child edge using unique node names
parentText = adaptor.getText(tree)
for i in range(n):
child = adaptor.getChild(tree, i)
childText = adaptor.getText(child)
childName = "n%d" % self.getNodeNumber(child)
edgeST = edgeST.getInstanceOf()
edgeST.setAttribute("parent", parentName)
edgeST.setAttribute("child", childName)
edgeST.setAttribute("parentText", parentText)
edgeST.setAttribute("childText", childText)
treeST.setAttribute("edges", edgeST)
self.toDOTDefineEdges(child, adaptor, treeST, edgeST)
def getNodeST(self, adaptor, t):
text = adaptor.getText(t)
nodeST = self._nodeST.getInstanceOf()
uniqueName = "n%d" % self.getNodeNumber(t)
nodeST.setAttribute("name", uniqueName)
if text is not None:
text = text.replace('"', r'\"')
nodeST.setAttribute("text", text)
return nodeST
def getNodeNumber(self, t):
try:
return self.nodeToNumberMap[t]
except KeyError:
self.nodeToNumberMap[t] = self.nodeNumber
self.nodeNumber += 1
return self.nodeNumber - 1
def toDOT(tree, adaptor=None, treeST=DOTTreeGenerator._treeST, edgeST=DOTTreeGenerator._edgeST):
"""
Generate DOT (graphviz) for a whole tree not just a node.
For example, 3+4*5 should generate:
digraph {
node [shape=plaintext, fixedsize=true, fontsize=11, fontname="Courier",
width=.4, height=.2];
edge [arrowsize=.7]
"+"->3
"+"->"*"
"*"->4
"*"->5
}
Return the ST not a string in case people want to alter.
Takes a Tree interface object.
Example of invokation:
import antlr3
import antlr3.extras
input = antlr3.ANTLRInputStream(sys.stdin)
lex = TLexer(input)
tokens = antlr3.CommonTokenStream(lex)
parser = TParser(tokens)
tree = parser.e().tree
print tree.toStringTree()
st = antlr3.extras.toDOT(t)
print st
"""
gen = DOTTreeGenerator()
return gen.toDOT(tree, adaptor, treeST, edgeST)