timers: Optimize _next_timer_interrupt() level iteration
If a level has a timer that expires before reaching the next level, there is no need to iterate further. The next level is reached when the 3 lower bits of the current level are cleared. If the next event happens before/during that, the next levels won't provide an earlier expiration. Signed-off-by: Frederic Weisbecker <frederic@kernel.org> Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Tested-by: Juri Lelli <juri.lelli@redhat.com> Link: https://lkml.kernel.org/r/20200717140551.29076-7-frederic@kernel.org
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@ -1526,6 +1526,7 @@ static unsigned long __next_timer_interrupt(struct timer_base *base)
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clk = base->clk;
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for (lvl = 0; lvl < LVL_DEPTH; lvl++, offset += LVL_SIZE) {
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int pos = next_pending_bucket(base, offset, clk & LVL_MASK);
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unsigned long lvl_clk = clk & LVL_CLK_MASK;
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if (pos >= 0) {
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unsigned long tmp = clk + (unsigned long) pos;
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@ -1533,6 +1534,13 @@ static unsigned long __next_timer_interrupt(struct timer_base *base)
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tmp <<= LVL_SHIFT(lvl);
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if (time_before(tmp, next))
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next = tmp;
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/*
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* If the next expiration happens before we reach
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* the next level, no need to check further.
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*/
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if (pos <= ((LVL_CLK_DIV - lvl_clk) & LVL_CLK_MASK))
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break;
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}
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/*
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* Clock for the next level. If the current level clock lower
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@ -1570,7 +1578,7 @@ static unsigned long __next_timer_interrupt(struct timer_base *base)
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* So the simple check whether the lower bits of the current
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* level are 0 or not is sufficient for all cases.
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*/
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adj = clk & LVL_CLK_MASK ? 1 : 0;
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adj = lvl_clk ? 1 : 0;
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clk >>= LVL_CLK_SHIFT;
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clk += adj;
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}
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