io: define stronger ordering for the default readX() implementation
The default implementation of mapping readX() to __raw_readX() is wrong. readX() has stronger ordering semantics. Compiler is allowed to reorder __raw_readX() against the memory accesses following register read. Use the previously defined __io_ar() and __io_br() macros to harden code generation according to architecture support. Signed-off-by: Sinan Kaya <okaya@codeaurora.org> Signed-off-by: Arnd Bergmann <arnd@arndb.de>
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@ -154,7 +154,12 @@ static inline void __raw_writeq(u64 value, volatile void __iomem *addr)
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#define readb readb
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static inline u8 readb(const volatile void __iomem *addr)
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{
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return __raw_readb(addr);
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u8 val;
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__io_br();
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val = __raw_readb(addr);
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__io_ar();
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return val;
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}
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#endif
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@ -162,7 +167,12 @@ static inline u8 readb(const volatile void __iomem *addr)
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#define readw readw
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static inline u16 readw(const volatile void __iomem *addr)
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{
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return __le16_to_cpu(__raw_readw(addr));
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u16 val;
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__io_br();
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val = __le16_to_cpu(__raw_readw(addr));
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__io_ar();
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return val;
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}
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#endif
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@ -170,7 +180,12 @@ static inline u16 readw(const volatile void __iomem *addr)
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#define readl readl
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static inline u32 readl(const volatile void __iomem *addr)
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{
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return __le32_to_cpu(__raw_readl(addr));
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u32 val;
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__io_br();
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val = __le32_to_cpu(__raw_readl(addr));
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__io_ar();
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return val;
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}
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#endif
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@ -179,7 +194,12 @@ static inline u32 readl(const volatile void __iomem *addr)
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#define readq readq
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static inline u64 readq(const volatile void __iomem *addr)
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{
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return __le64_to_cpu(__raw_readq(addr));
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u64 val;
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__io_br();
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val = __le64_to_cpu(__raw_readq(addr));
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__io_ar();
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return val;
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}
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#endif
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#endif /* CONFIG_64BIT */
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