drm/amdgpu: make vmid owner be client_id
Using the pointer is not adequate. Signed-off-by: Chunming Zhou <David1.Zhou@amd.com> Reviewed-by: Alex Deucher <alexander.deucher@amd.com> Reviewed-by: Monk Liu <monk.liu@amd.com> Signed-off-by: Alex Deucher <alexander.deucher@amd.com>
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@ -185,7 +185,7 @@ int amdgpu_vm_grab_id(struct amdgpu_vm *vm, struct amdgpu_ring *ring,
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if (!id)
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continue;
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if (atomic_long_read(&id->owner) != (long)vm)
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if (atomic_long_read(&id->owner) != vm->client_id)
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continue;
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if (pd_addr != id->pd_gpu_addr)
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@ -261,7 +261,7 @@ int amdgpu_vm_grab_id(struct amdgpu_vm *vm, struct amdgpu_ring *ring,
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list_move_tail(&id->list, &adev->vm_manager.ids_lru);
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id->last_user = ring;
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atomic_long_set(&id->owner, (long)vm);
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atomic_long_set(&id->owner, vm->client_id);
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vm->ids[ring->idx] = id;
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*vm_id = id - adev->vm_manager.ids;
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@ -1485,7 +1485,7 @@ void amdgpu_vm_fini(struct amdgpu_device *adev, struct amdgpu_vm *vm)
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list) {
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if (!id)
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continue;
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if (atomic_long_read(&id->owner) == (long)vm) {
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if (atomic_long_read(&id->owner) == vm->client_id) {
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atomic_long_set(&id->owner, 0);
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id->pd_gpu_addr = 0;
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}
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