net/mlx4_en: Resolve dividing by zero in 32-bit system
When doing roundup_pow_of_two for large enough number with
bit 31, an overflow will occur and a value equal to 1 will
be returned. In this case 1 will be subtracted from the return
value and division by zero will be reached.
Fixes: 31c128b66e
("net/mlx4_en: Choose time-stamping shift value according to HW frequency")
Signed-off-by: Eugenia Emantayev <eugenia@mellanox.com>
Signed-off-by: Tariq Toukan <tariqt@mellanox.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
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@ -245,8 +245,11 @@ static u32 freq_to_shift(u16 freq)
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{
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u32 freq_khz = freq * 1000;
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u64 max_val_cycles = freq_khz * 1000 * MLX4_EN_WRAP_AROUND_SEC;
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u64 tmp_rounded =
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roundup_pow_of_two(max_val_cycles) > max_val_cycles ?
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roundup_pow_of_two(max_val_cycles) - 1 : UINT_MAX;
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u64 max_val_cycles_rounded = is_power_of_2(max_val_cycles + 1) ?
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max_val_cycles : roundup_pow_of_two(max_val_cycles) - 1;
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max_val_cycles : tmp_rounded;
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/* calculate max possible multiplier in order to fit in 64bit */
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u64 max_mul = div_u64(0xffffffffffffffffULL, max_val_cycles_rounded);
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