pinctrl: sprd: Add of_node_put() before return to prevent memory leak
Each iteration of for_each_child_of_node puts the previous node, but in the case of a return from the middle of the loop, there is no put, thus causing a memory leak. Hence add an of_node_put before the return in two places. Issue found with Coccinelle. Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com> Link: https://lore.kernel.org/r/20190808074329.15579-1-nishkadg.linux@gmail.com Reviewed-by: Baolin Wang <baolin.wang@linaro.org> Signed-off-by: Linus Walleij <linus.walleij@linaro.org>
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@ -925,8 +925,10 @@ static int sprd_pinctrl_parse_dt(struct sprd_pinctrl *sprd_pctl)
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for_each_child_of_node(np, child) {
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ret = sprd_pinctrl_parse_groups(child, sprd_pctl, grp);
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if (ret)
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if (ret) {
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of_node_put(child);
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return ret;
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}
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*temp++ = grp->name;
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grp++;
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@ -935,8 +937,11 @@ static int sprd_pinctrl_parse_dt(struct sprd_pinctrl *sprd_pctl)
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for_each_child_of_node(child, sub_child) {
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ret = sprd_pinctrl_parse_groups(sub_child,
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sprd_pctl, grp);
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if (ret)
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if (ret) {
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of_node_put(sub_child);
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of_node_put(child);
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return ret;
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}
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*temp++ = grp->name;
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grp++;
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