btrfs: make success path out of btrfs_init_dev_replace_tgtdev more clear
This is a preparatory cleanup that will make clear that the only successful way out of btrfs_init_dev_replace_tgtdev will also set the device_out to a valid pointer. With this guarantee, the callers can be simplified. Reviewed-by: Anand Jain <anand.jain@oracle.com> Signed-off-by: David Sterba <dsterba@suse.com>
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@ -358,7 +358,6 @@ int btrfs_dev_replace_start(struct btrfs_fs_info *fs_info,
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dev_replace->cont_reading_from_srcdev_mode = read_src;
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WARN_ON(!src_device);
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dev_replace->srcdev = src_device;
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WARN_ON(!tgt_device);
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dev_replace->tgtdev = tgt_device;
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btrfs_info_in_rcu(fs_info,
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@ -2612,6 +2612,12 @@ int btrfs_init_new_device(struct btrfs_fs_info *fs_info, const char *device_path
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return ret;
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}
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/*
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* Initialize a new device for device replace target from a given source dev
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* and path.
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*
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* Return 0 and new device in @device_out, otherwise return < 0
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*/
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int btrfs_init_dev_replace_tgtdev(struct btrfs_fs_info *fs_info,
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const char *device_path,
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struct btrfs_device *srcdev,
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@ -2698,7 +2704,7 @@ int btrfs_init_dev_replace_tgtdev(struct btrfs_fs_info *fs_info,
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mutex_unlock(&fs_info->fs_devices->device_list_mutex);
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*device_out = device;
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return ret;
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return 0;
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error:
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blkdev_put(bdev, FMODE_EXCL);
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