of: alloc anywhere from memblock if range not specified
early_init_dt_alloc_reserved_memory_arch passes end as 0 to __memblock_alloc_base, when limits are not specified. But __memblock_alloc_base takes end value of 0 as MEMBLOCK_ALLOC_ACCESSIBLE and limits the end to memblock.current_limit. This results in regions never being placed in HIGHMEM area, for e.g. CMA. Let __memblock_alloc_base allocate from anywhere in memory if limits are not specified. Acked-by: Marek Szyprowski <m.szyprowski@samsung.com> Signed-off-by: Vinayak Menon <vinmenon@codeaurora.org> Cc: stable@vger.kernel.org Signed-off-by: Rob Herring <robh@kernel.org>
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@ -32,11 +32,13 @@ int __init __weak early_init_dt_alloc_reserved_memory_arch(phys_addr_t size,
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phys_addr_t align, phys_addr_t start, phys_addr_t end, bool nomap,
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phys_addr_t align, phys_addr_t start, phys_addr_t end, bool nomap,
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phys_addr_t *res_base)
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phys_addr_t *res_base)
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{
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{
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phys_addr_t base;
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/*
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/*
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* We use __memblock_alloc_base() because memblock_alloc_base()
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* We use __memblock_alloc_base() because memblock_alloc_base()
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* panic()s on allocation failure.
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* panic()s on allocation failure.
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*/
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*/
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phys_addr_t base = __memblock_alloc_base(size, align, end);
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end = !end ? MEMBLOCK_ALLOC_ANYWHERE : end;
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base = __memblock_alloc_base(size, align, end);
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if (!base)
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if (!base)
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return -ENOMEM;
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return -ENOMEM;
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