scsi: sg: Use mult_frac, drop MULDIV macro
The MULDIV macro is essentially a duplicate of the more standard mult_frac macro. Replace use of MULDIV with mult_frac & drop the duplication. Signed-off-by: Paul Burton <paul.burton@imgtec.com> Acked-by: Douglas Gilbert <dgilbert@interlog.com> Signed-off-by: Martin K. Petersen <martin.petersen@oracle.com>
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@ -79,18 +79,7 @@ static void sg_proc_cleanup(void);
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*/
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#define SG_MAX_CDB_SIZE 252
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/*
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* Suppose you want to calculate the formula muldiv(x,m,d)=int(x * m / d)
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* Then when using 32 bit integers x * m may overflow during the calculation.
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* Replacing muldiv(x) by muldiv(x)=((x % d) * m) / d + int(x / d) * m
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* calculates the same, but prevents the overflow when both m and d
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* are "small" numbers (like HZ and USER_HZ).
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* Of course an overflow is inavoidable if the result of muldiv doesn't fit
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* in 32 bits.
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*/
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#define MULDIV(X,MUL,DIV) ((((X % DIV) * MUL) / DIV) + ((X / DIV) * MUL))
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#define SG_DEFAULT_TIMEOUT MULDIV(SG_DEFAULT_TIMEOUT_USER, HZ, USER_HZ)
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#define SG_DEFAULT_TIMEOUT mult_frac(SG_DEFAULT_TIMEOUT_USER, HZ, USER_HZ)
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int sg_big_buff = SG_DEF_RESERVED_SIZE;
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/* N.B. This variable is readable and writeable via
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@ -884,11 +873,11 @@ sg_ioctl(struct file *filp, unsigned int cmd_in, unsigned long arg)
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return result;
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if (val < 0)
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return -EIO;
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if (val >= MULDIV((s64)INT_MAX, USER_HZ, HZ))
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val = min_t(s64, MULDIV((s64)INT_MAX, USER_HZ, HZ),
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if (val >= mult_frac((s64)INT_MAX, USER_HZ, HZ))
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val = min_t(s64, mult_frac((s64)INT_MAX, USER_HZ, HZ),
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INT_MAX);
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sfp->timeout_user = val;
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sfp->timeout = MULDIV (val, HZ, USER_HZ);
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sfp->timeout = mult_frac(val, HZ, USER_HZ);
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return 0;
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case SG_GET_TIMEOUT: /* N.B. User receives timeout as return value */
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